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Jefferson's old bedroom was shaped like a rectangle. It had a length that was 5 times its width. When Jefferson's family moved, his new bedroom was also shaped like a rectangle. It was 3 feet longer and 2 feet wider than his old bedroom. If w represents the width of Jefferson's bedroom, what expression represents the difference between the area of his new bedroom and the area of his old bedroom?

User Sbenderli
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2 Answers

3 votes

Answer:

(5w+3)(w+2)

Explanation:

5w x w = a

The new room is 3 ft longer and 2 ft wider so the new equation is

(5w+3)(w+2)

User Chintan Hingrajiya
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3 votes

Answer:


\sf \textsf{Difference} = (5w + 3)(w + 2) - 5w^2

Explanation:

Let's denote the width of Jefferson's old bedroom as
\sf w. Given that the length of the old bedroom is 5 times its width, the length (
\sf l) of the old bedroom is
\sf 5w.

The area (
\sf A) of the old bedroom is given by the product of its length and width:


\sf A_{\textsf{old}} = l * w = (5w) * w = 5w^2

Now, Jefferson's new bedroom is 3 feet longer and 2 feet wider than his old bedroom. Therefore, the length of the new bedroom (
\sf L_{\textsf{new}}) is
\sf 5w + 3, and the width (
\sf W_{\textsf{new}}) is
\sf w + 2.

The area (
\sf A_{\textsf{new}}) of the new bedroom is given by the product of its length and width:


\sf A_{\textsf{new}} = L_{\textsf{new}} * W_{\textsf{new}} = (5w + 3) * (w + 2)

Now, we want to find the expression that represents the difference between the area of the new bedroom and the area of the old bedroom:


\sf \textsf{Difference} = A_{\textsf{new}} - A_{\textsf{old}}


\sf \textsf{Difference} = (5w + 3)(w + 2) - 5w^2

So, the expression to represent the difference between the area of his new bedroom and the area of his old bedroom is:


\sf \textsf{Difference} = (5w + 3)(w + 2) - 5w^2

User Jon Limjap
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