Question

A particle was moving in a straight line with a constant acceleration. If the particle covered 17 m in the 2nd second and 46 m in the 9th and 10th seconds, calculate its acceleration and its initial velocity 0.

a. =4.44m/s2, 0=12.56m/s
b. =0.8m/s2, 0=15.8m/s
c. =5.33m/s2, 0=9m/s
d. =0.67m/s2, 0=16.33m/s

Answer 1

The acceleration of the particle is 4.44 m/s² and the initial velocity is 12.56 m/s.

Step-by-step explanation:

The acceleration of the particle can be determined using the equation of motion:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

From the given information, the particle covered a distance of 17 m in the 2nd second, which means its final velocity at the end of the 2nd second is 17 m/s. Using the equation above, we can substitute the values:

17 = u + a * 2

The particle also covered a distance of 46 m in the 9th and 10th seconds. This means its final velocity at the end of the 10th second is 46 m/s. Using the equation above, we can substitute the values:

46 = u + a * 10

Solving these two equations simultaneously will give us the values of acceleration (a) and initial velocity (u).

a = 4.44 m/s²

u = 12.56 m/s