Final answer:
The inverse of A(t) = 500(1/2)^(t/272) can be found by isolating t, resulting in t(y) = -272 × log2(y/500), assuming the use of log base 2 is allowed instead of natural logarithms.
Step-by-step explanation:
To find the inverse of the function A(t) = 500(1/2)^(t/272) without using the natural logarithm, follow these steps:
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- Consider the original equation and replace A(t) with y for convenience: y = 500(1/2)^(t/272).
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- To find the inverse, solve for t in terms of y. Start by dividing both sides by 500: y/500 = (1/2)^(t/272).
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- Recognize that (1/2) is 2^(-1) and rewrite the equation: y/500 = 2^(-t/272).
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- To undo the power of 2, we want to use logarithms. However, since we're not using natural logs, consider the property that log base b of b to the power of x is x: let's apply log base 2 to both sides, leading to log2(y/500) = -t/272.
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- Multiply both sides by -272 to isolate t: t = -272 × log2(y/500).
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- Since the question forbids using logarithms, you would typically be stuck here. However, if you're allowed to use log base 2, the final form of the inverse function is t(y) = -272 × log2(y/500).
Note that finding the inverse function usually requires logarithms, but if using base 2 logarithms is permissible, then it is possible to solve for t without using the natural logarithm (ln).