The magnitude of the force is 90 N, the location of the force is 0.7 m from the left end of the bar and the direction of the force is Upwards.
∑F = 0
60 N force acting downwards at the left end of the bar
80 N force acting downwards at 0.6 m from the left end of the bar
50 N force acting upwards at 0.4 m from the left end of the bar
60 N + 80 N - 50 N -F = 0
F= 90 N
The location of the force is
∑τ = 0
60 N * 1 m + 80 N * 0.6 m - 50 N * 0.4 m -F * x = 0
x = 0.7 m
The direction of the force needed to keep the bar in equilibrium must be upwards because the other three forces are all acting downwards.