Question

A bus starts to move with acceleration of 1ms^-2. a man who is 48m behind the bus runs to catch it with a constant velocity of 10m/s. in how much time will he catch the bus??

Answer 1

The man will catch the bus in approximately 4.8 seconds.

Step-by-step explanation:

To find the time it takes for the man to catch the bus, we need to calculate the time it takes for the man to cover the initial distance of 48m at his constant velocity of 10m/s. The formula for time is:

time = distance / speed

Substituting the values we have:

time = 48m / 10m/s = 4.8s

Therefore, it will take the man approximately 4.8 seconds to catch the bus.