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The following is a random sample of the annual salaries of high school counselors in the united states. assuming that the distribution of salaries is approximately normal, construct a 99% confidence interval for the mean salary of high school counselors across the united states. round to the nearest dollar.

$61,120 $52,730 $53,290 $36,550 $34,790 $61,250 $61,900

User Cvarsendan
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Final answer:

To construct a 99% confidence interval for the mean salary of high school counselors in the United States, calculate the sample mean and standard deviation. Use the t-distribution with the appropriate critical value to find the standard error. Then use the formula to calculate the confidence interval.

Step-by-step explanation:

To construct a 99% confidence interval for the mean salary of high school counselors across the United States, we can use the formula:

Confidence Interval = (sample mean) +/- (critical value * standard error)

Step 1: Calculate the sample mean, which is the average of the given salaries: ($61,120 + $52,730 + $53,290 + $36,550 + $34,790 + $61,250 + $61,900) / 7 = $51,601.43 (rounded to the nearest dollar).

Step 2: Calculate the standard deviation of the sample, which is a measure of the variability: $11,037.48 (rounded to the nearest dollar).

Step 3: Calculate the standard error, which is the standard deviation divided by the square root of the sample size. Since this is a small sample size of 7, we can use the t-distribution instead of the z-distribution (since the sample is less than 30). The critical value for a 99% confidence level and 6 degrees of freedom (n-1) is 3.707 (rounded to three decimal places), which we can find from a t-table or a statistical software.

Step 4: Calculate the confidence interval:

Confidence Interval = $51,601.43 +/- (3.707 * ($11,037.48/√7) )

Confidence Interval = $51,601.43 +/- $15,514.87

Confidence Interval ≈ $36,086.56 to $67,116.30 (rounded to the nearest dollar)

User Stefan Charsley
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