Final answer:
The buffer consists of HSO4- as the acid component and SO42- as the base component. When a base such as 2-propanamine is present, it reacts with HSO4-. In the presence of OH-, HSO4- donates a proton, forming water and SO42-.
Step-by-step explanation:
The buffer solution in question consists of hydrogen sulfate (HSO4-) and sulfate (SO42-). The acid component of this buffer is HSO4-, which can donate a proton, and the base component is SO42-, which can accept protons. In the context of 2-propanamine, which is a base, it will react with the acid component of the buffer.
For instance, when a strong base like hydroxide ions (OH-) are added to the buffer, the following reaction could occur:
- HSO4-(aq) + OH-(aq) → SO42-(aq) + H2O(l)
This shows that HSO4- acts as an acid by donating a proton to OH-, creating water and the base component SO42- of the buffer.