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(Left Shifting Integers ) Left shifting an unsigned int by 1 bit is equivalent to multiplying the value by

User Korona
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Final answer:

Left shifting an unsigned int by 1 bit doubles its value, which is equivalent to multiplying the original number by 2.

Step-by-step explanation:

Left shifting an unsigned int by 1 bit is equivalent to multiplying the value by 2. This is because in binary, moving bits to the left by one position is similar to how in decimal you would move all the digits one place to the left when multiplying by 10.

Each shift to the left actually doubles the number, so if you have an integer value such as 5, which is 101 in binary, and you shift it left by 1 bit, it becomes 1010 in binary, which is 10 in decimal.

Left shifting an unsigned int by 1 bit is equivalent to multiplying the value by 2.

When an unsigned int is left shifted by 1 bit, each digit in its binary representation is shifted one place to the left and a '0' is added as the least significant bit. This is equivalent to multiplying the original value by 2.

For example, if the original unsigned int is 5 (represented as 00000101 in binary), left shifting it by 1 bit gives us 10 (represented as 00001010 in binary), which is equal to 2 times the original value.

User Ries
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