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How many molecules of water can be produced by reacting 0.010 mol of oxygen with hydrogen?

H₂(g) + O₂(g) -> H₂O(l) (unbalanced)

User Aus
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Final answer:

A 0.010 mol of oxygen can produce 0.020 mol of water which equals approximately 1.2044 × 1022 water molecules when reacted with hydrogen according to the balanced chemical equation.

Step-by-step explanation:

The question at hand involves a typical stoichiometry problem in chemistry, where we need to determine the number of water molecules produced when a specific amount of oxygen reacts with hydrogen. From the balanced chemical equation 2 H2(g) + O2(g) → 2 H2O(l), we know that one mole of oxygen reacts to yield two moles of water.

Thus, if you have 0.010 mol of oxygen, according to the balanced equation, this will produce twice as many moles of water, which is 0.020 mol of water. To find the number of molecules, we multiply this amount by Avogadro's number (6.022 × 1023 molecules/mol), resulting in approximately 1.2044 × 1022 water molecules.

User Rockbot
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