Answer:
- length: 15 meters
- width: 68 meters
Explanation:
You want the length and width of a rectangle whose length is an odd integer and whose width is 4 times the next consecutive odd integer. The perimeter is 166 meters.
Setup
Let x represent the length of the rectangle. Then the width is 4(x+2), and the perimeter is ...
P = 2(L+W)
166 = 2(x +4(x+2))
Solution
166 = 10x +16 . . . . . . simplify
150 = 10x . . . . . . . . . subtract 16
15 = x . . . . . . . . . . . divide by 10
4(x+2) = 4(15 +2) = 68 . . . . . width
The length of the rectangle is 15 meters; the width is 68 meters.