Question

A toy car moves 3.0 m to the north in one second. the car then moves at 9.0 m/s due south for two seconds. what is the average speed of the car for this three second trip? group of answer choices

O 4.0 m/s
O 5.0 m/s
O 6.0 m/s
O 7 m/s

Answer 1

The average speed of the toy car for the trip is calculated by dividing the total displacement by the total time, which results in an average speed of 5.0 m/s.

Step-by-step explanation:

The question asks to calculate the average speed of the toy car over a three-second trip in which it first moves 3.0 m north in one second and then moves 9.0 m/s south for two seconds. To find the average speed, you need to divide the total distance traveled by the total time taken.

First, we calculate the distance moved south in two seconds: 9.0 m/s × 2 s = 18.0 m. The car moves 3.0 m north and 18.0 m south, which are in opposite directions. Thus, we consider the magnitude of total displacement, which is 18.0 m - 3.0 m = 15.0 m in three seconds. The average speed is then the total displacement divided by the total time, so:

Average speed = Total Displacement / Total Time

Average speed = 15.0 m / 3 s = 5.0 m/s.

Therefore, the average speed of the car for this trip is 5.0 m/s.