Question

The synthesis of the pesticide thionyl chloride (OSCl) proceeds according to:

SO₃(g) + SCI₂ (OSCl₂(l)+SO₂(g) If△G' =-106 kJ/mol for this reaction at 298K, what is the K, at this temperature? Recall: R = 8.314 J moPF
a. 3.81 × 10¹⁸
b. 7.21 × 10¹²
c. 1.19× 10²⁰
d. 3.50 x 10¹⁴

Answer 1

To find the equilibrium constant (K) for the reaction SO3(g) + SCl2(g) → SOCl2(l) + SO2(g), use the provided ΔG' and the equation ΔG' = -RT ln K. Substituting the values and solving, K is approximately 6.14 × 1018, which is closest to option (a) 3.81 × 1018.

Step-by-step explanation:

The synthesis of the pesticide thionyl chloride (OSCl) can be analyzed using the reaction: SO3(g) + SCl2(g) → SOCl2(l) + SO2(g) and the given standard free energy change (ΔG' = -106 kJ/mol) at temperature 298K. To calculate the equilibrium constant (K) for this reaction, we use the relationship ΔG' = -RT ln K, where R is the universal gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin. Substituting the given ΔG' and the other values into the equation, we get:

ΔG' = -RT ln K

ΔG' = -106,000 J/mol

R = 8.314 J/(mol·K)

T = 298 K

Rearranging the equation to solve for K, we have:

ln K = - ΔG' / (RT)

ln K = -(-106,000 J/mol) / ((8.314 J/(mol·K))(298 K))

ln K = -(-106,000) / (2468.132)

ln K = 42.958

K = e42.958

When you calculate the value of K using the exponential function, you will find it equals approximately 6.14 × 1018, which matches closest to option (a) 3.81 × 1018.