Final answer:
The compound with the greatest mass of nitrogen among the given options is (c) 1.5 moles of (NH₄)₃PO₄, which contains 63 grams of nitrogen.The correct answer is option c.
Step-by-step explanation:
To determine which compound contains the greatest mass of nitrogen, we need to calculate the masses of nitrogen in each option by accounting for the number of moles of each compound and the number of nitrogen atoms per molecule. We'll use the molar mass of nitrogen (14 g/mol) for these calculations.
- (a) (NH₄)₂SO₄ has 2 moles of NH₄, therefore 0.5 moles of (NH₄)₂SO₄ contain 1 mole of N, which is 14 g.
- (b) NH₄NO₃ has 2 moles of N, so 1 mole of NH₄NO₃ contains 2 moles of N, which is 28 g.
- (c) (NH₄)₃PO₄ has 3 moles of NH₄, therefore 1.5 moles of (NH₄)₃PO₄ contain 4.5 moles of N, which is 63 g.
- (d) CO(NH)₂ has 1 mole of N, so 2 moles of CO(NH)₂ contain 2 moles of N, which is 28 g.
Comparing the masses of nitrogen in the given options, compound (c) (NH₄)₃PO₄ has the greatest mass of nitrogen at 63 g. Therefore, the correct option is (c) 1.5 moles (NH₄)₃PO₄.