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the intensity of an em wave is 7.63 w/m². the wave is incident upon a rectangular area, 1.19 m by 9.38 m. the wave's direction of propagation is normal to the surface. how much total electromagnetic energy falls on the area during 8.73 seconds?

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Final answer:

To determine the total electromagnetic energy that falls on a rectangle, calculate the area, use the intensity to find the power, and multiply by the time to get the energy. The calculation leads to a total energy of 743.19501658 Joules over the duration of 8.73 seconds.

Step-by-step explanation:

The student has asked how much total electromagnetic energy falls on a rectangular area during a specific time period. To find this out, we can use the relationship that intensity (I) is the power per unit area with units in W/m². Since the wave's direction of propagation is normal to the surface, we can directly multiply the intensity by the area to find the power and then multiply the power by the time to find the energy.

Calculate the area of the rectangle: Area = length × width = 1.19 m × 9.38 m.

Multiply the intensity by the area to find the power: Power = Area × Intensity.

Multiply the power by the time duration to find the total energy: Energy = Power × Time.

Following these steps:

Area = 1.19 m × 9.38 m = 11.1622 m².

Power = 11.1622 m² × 7.63 W/m² = 85.148366 W.

Total Energy = 85.148366 W × 8.73 s = 743.19501658 J.

Therefore, 743.19501658 Joules of electromagnetic energy fall on the rectangle over the duration of 8.73 seconds.

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