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an investigator wants to estimate caffeine consumption in high school students. how many students would be required to ensure that a 95% confidence interval estimate for the mean caffeine intake (measured in mg) is within 15 mg of the true mean? assume that the standard deviation in caffeine intake is 68 mg.

User Parameswar
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Final answer:

To calculate the sample size needed for a 95% confidence interval within 15 mg of the true mean caffeine intake with a standard deviation of 68 mg, use the formula n = (z*σ/E)^2. Approximately 1096 high school students should be sampled.

Step-by-step explanation:

To estimate caffeine consumption in high school students and determine the sample size required to ensure that a 95% confidence interval estimate for the mean caffeine intake is within 15 mg of the true mean, one can use the sample size formula for a mean:

n = (z*σ/E)^2

Where:

  • n is the sample size
  • z is the z-score corresponding to the desired confidence level (1.96 for 95%)
  • σ (sigma) is the population standard deviation
  • E is the desired margin of error

Given a standard deviation (σ) of 68 mg and a margin of error (E) of 15 mg:

n = (1.96*68/15)^2

n ≈ 33.08^2

n ≈ 1095.3864

Thus, the investigator would need to sample approximately 1096 students (since we cannot have a fraction of a student) to be 95% confident that the sample mean is within 15 mg of the true population mean caffeine intake.

User Maximilian Stroh
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