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You go to work at a company that pays $0.01 for the first day, $0.02 for the second day, $0.04 for the third day, and so on. If the daily wage keeps doubling, what would your total income be (in dollars) for working the following number of days? (Round your answers to two decimal places.)

A) 3 days
B) 5 days
C) 10 days
D) 20 days

User Hadja
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1 Answer

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Final answer:

The total income after working for various numbers of days in a job where the pay doubles each day is calculated by the geometric series formula. For 3 days, the sum is $0.07; for 5 days, it's $0.31; for 10 days, it's $10.23; and for 20 days, a surprisingly large total of $10,485.75 is reached due to exponential growth. A) 3 days

Step-by-step explanation:

The scenario presented is a classic example of a geometric progression where the daily wage doubles each day, which is a common mathematical concept covered in middle school math curriculum. The wage progression follows the pattern of 2n-1 where n is the day number. The total income for a certain number of days is the sum of a geometric series.

  • For 3 days: $0.01 + $0.02 + $0.04 = $0.07
  • For 5 days: $0.01 + $0.02 + $0.04 + $0.08 + $0.16 = $0.31
  • For 10 days: The total is $0.01(210 - 1) / (2 - 1) = $10.23
  • For 20 days: The total is $0.01(220 - 1)/(2 - 1) = $10,485.75

To calculate the total income precisely, we apply the formula for the sum of the first n terms of a geometric series: Sn = a(1 - rn) / (1 - r), with 'a' being the first term and 'r' the common ratio. Here, 'a' is $0.01, and 'r' is 2. It's important to note that for practical and real-life applications, understanding the concept of exponential growth, similar to how interest accumulates in a bank account or the growth rate when given a pay raise, is essential.

User Mark Van Lent
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