Question

Help me with question #5 please

Answer 1

see explanation

Explanation:

consider left side

1 -
`(cos^20)/(1+sin0)`

using the identity

sin² Θ + cosΘ² = 1 ( subtract sin²Θ from both sides )

cos²Θ = 1 - sin²Θ , then

1 -
`(1-sin^20)/(1+sin0)` ← 1 - sin²Θ is a difference of squares

= 1 -
`((1+sin0)(1-sino))/(1+sin0)` ← cancel ( 1 + sinΘ ) on numerator/ denominator

= 1 - (1 - sinΘ )

= 1 - 1 + sinΘ

= sinΘ = right side

hence proven