Question

A sample of argon gas at stp occupies 56. 2 liters. Determine the mass of argon in the sample.

Answer 1

`\huge{\boxed{100.4 \: g}}`

Step-by-step explanation:

In order to find the mass of the gas we must first find the number of moles of the gas at STP ( standard temperature and pressure) and use it together with the molar mass of the gas.

In order to find the number of moles from the volume given we use the formula;

`n = (V)/(v_(m))\\`

where

V is the volume of the gas

n is the number of moles

v(m) is the molar gas volume at stp which is

22.4 L/mol

From the question

V = 56.2 L

We have;

`n = (56.2)/(22.4) = 2.508 \\`

n = 2.51 moles

Now we use the formula m = M × n to find the mass of the gas

where

m is the mass

M is the molar mass

Molar mass of Argon = 40 g/mol

We have

m = 40 × 2.51 =. 100.4

We have the final answer as:

100.4 g