Question

Whats the nth term of -13, -25, -37, -49?

Answer 1

Answer:
`a_(n) = -12n-1`

Consider the difference between the consecutive terms

-25-(-13) = -12

-37-(-25) = -12

-49-(-37) = -12

The difference (d) is constant and equals -12.

Therefore, this sequence is an "Arithmetic sequence"

initial terms (a) = -13

From

`a_(n) = a+(n-1)d` (
`a_(n)` is the n-th term of the sequence)

`a_(n) = -13 + (n-1)(-12)`

`a_(n) =-13-12n+12`

Therefore,
`a_(n) = -12n-1`