Answer:
see explanation
Explanation:
substitute x = 0 and x = 1 into the polynomial and evaluate
0³ + 6(0) - 5 = 0 + 0 - 5 = - 5
1³ + 6(1) - 5 = 1 + 6 - 5 = 2
since polynomial < 0 at x = 0 and > 0 at x = 1
Then the graph crosses the x- axis between 0 and 1
This indicates the solution lies between x = 0 and x = 1