Question

What is the output of the following code?

1) int value provided
2) float value provided
3) Invalid type provided
4) Value of x: 600


void process(void *dataPtr, int type) {
int a;
double b;

if (type == 1) {
a = *((int *)dataPtr);
printf(""int value provided %d\\"", a);
} else if (type == 2) {
b = *((float *)dataPtr);
printf(""float value provided %f\\"", b);
} else {
printf(""Invalid type provided\\"");
}
}

int main() {
int x = 200;
float y = 4.4;
int *xPtr;
void *vPtr;

/* You can assign any address to a void pointer */
vPtr = &y; /* assigning pointer to float */
vPtr = &x; /* assigning pointer to int */

/* We cannot dereference void ptr */
/* *vPtr = 100; */

*((int *)vPtr) = 400;
printf(""Value of x: %d\\"", x);

xPtr = (int *)vPtr;
*xPtr = 600;
printf(""Value of x: %d\\"", x);

/* Void pointers allow us to pass any data */
process(&x, 1);
process(&y, 2);

return 0;
}"

Answer 1

The output of the code will be the value of x changed to 400 and then 600, followed by the values from process function.

Step-by-step explanation:

The output of the code will be:

1. Value of x: 400
2. Value of x: 600
3. int value provided 600
4. float value provided 4.400000

In this code, a void pointer (vPtr) is used to store the addresses of both an int and a float variable. By casting the void pointer to the appropriate type and dereferencing it, we can retrieve the value stored at that address. The process function takes a void pointer and an integer type as arguments and uses casting to correctly retrieve and print the value of the passed variable based on its type.