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Solve this literal simultaneous equation for x and y.


ax+by=c

bx+ay=c

User Mickalot
by
8.3k points

1 Answer

5 votes

Answer:

The answer is below

Explanation:

Firstly, let us find the value of x. Multiply the first equation by a and the second equation by b to get:

a²x + aby = ca (3)

b²x + aby = cb (4)

Subtract equation 4 from equation 3 to get:

x(a² - b²) = c(a - b)

but a² - b² = (a + b)(a - b)

x(a + b)(a - b) = c(a - b)

x(a + b) = c


x=(c)/(a+b)

Secondly, let us find the value of y. Multiply the first equation by b and the second equation by a to get:

abx + b²y = cb (5)

abx + a²y = ca (6)

Subtract equation 5 from equation 6 to get:

y(a² - b²) = c(a - b)

but a² - b² = (a + b)(a - b)

y(a + b)(a - b) = c(a - b)

y(a + b) = c


y=(c)/(a+b)

User Bernard Polman
by
8.4k points

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