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Es en forma polinomial

User Koffiman
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The polynomial x^2 + 2x - 3 has zeroes 1 and -3, and the relation between the coefficients and zeroes is verified.

Polynomial with zeroes 1 and -3:

The zeroes of a polynomial are the values of x that make the equation equal to 0. Therefore, we need to construct a polynomial where x = 1 and x = -3 make the equation equal to 0.

Step 1: Construct the polynomial

We know that a polynomial with zeroes at 1 and -3 can be factored as follows:

(x - 1)(x + 3) = 0

Expanding this expression gives us the quadratic polynomial:

x^2 + 2x - 3 = 0

Step 2: Verify the relation between coefficients and zeroes

There is a relationship between the coefficients of a polynomial and its zeroes. For a quadratic polynomial of the form:

ax^2 + bx + c = 0

The sum of the zeroes is equal to -b/a and the product of the zeroes is equal to c/a.

In our case:

a = 1

b = 2

c = -3

Therefore, according to the relationship:

Sum of zeroes = -b/a = -2/1 = -2

Product of zeroes = c/a = -3/1 = -3

Checking with our zeroes 1 and -3:

Sum of zeroes = 1 + (-3) = -2 (correct)

Product of zeroes = 1 * (-3) = -3 (correct)

Therefore, the polynomial x^2 + 2x - 3 has zeroes 1 and -3, and the relation between the coefficients and zeroes is verified.

Complete question:

Forma de polynomial whose zeroes are 1 & -3.

Verify the relation between the coefficients & the zeroes of

the polynomial​

User Bebben
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