Question

Light with a wavelength of 500 nm (5. 10-7 m) is incident upon a double slit with a separation of 0.17 mm (1.70 10-4 m). A screen is located 1.8 m from the double slit. At what distance from the center of the screen will the first bright fringe beyond the center fringe appear?

Answer 1

The first bright fringe beyond the center fringe in a double-slit experiment can be found using the formula: y = m(lambda)L/d

Step-by-step explanation:

The first bright fringe beyond the center fringe in a double-slit experiment can be found using the formula:

y = m(lambda)L/d

Where:

• y represents the distance from the center of the screen to the fringe
• m is the order of the fringe (in this case, m = 1 for the first bright fringe)
• lambda is the wavelength of the light (500 nm or 5.10^-7 m)
• L is the distance from the double slit to the screen (1.8 m)
• d is the separation between the slits (0.17 mm or 1.70 10^-4 m)

Plugging in the values, we get:

y = (1)(5.10^-7 m)(1.8 m)/(1.70 10^-4 m) ≈ 9.53 mm

Therefore, the first bright fringe beyond the center fringe will appear at approximately 9.53 mm from the center of the screen.