Question

Enthalpy of solution of BaCl₂·2H₂O and BaCl₂ are 8.8 and 20.6 kJ mol⁻¹, respectively. Calculate the heat of hydration of BaCl₂ to BaCl₂·2H₂O.

a. 11.8 kJ mol⁻¹
b. 12.6 kJ mol⁻¹
c. 9.6 kJ mol⁻¹
d. 10.8 kJ mol⁻¹

Answer 1

The heat of hydration of BaCl₂ to BaCl₂·2H₂O is 11.8 kJ/mol.

Step-by-step explanation:

The enthalpy of solution for BaCl₂·2H₂O is 8.8 kJ/mol, while the enthalpy of solution for BaCl₂ is 20.6 kJ/mol. To calculate the heat of hydration, we need to find the difference in enthalpies between these two compounds. The heat of hydration can be calculated by subtracting the enthalpy of solution of BaCl₂ from the enthalpy of solution of BaCl₂·2H₂O. So, the heat of hydration of BaCl₂ to BaCl₂·2H₂O is 20.6 kJ/mol - 8.8 kJ/mol = 11.8 kJ/mol.