Question

Calculate the resistance of 0.01N solution of an electrolyte whose equivalent conductivity is 420Ω^−1cm^2equiv^−1 (the cell constant of the cell is 0.88cm^−1).

Answer 1

The resistance of a 0.01N solution of an electrolyte with an equivalent conductivity of 420Ω⁻¹cm²equiv⁻¹ and a cell constant of 0.88cm⁻¹ is 2.7mΩ.

Step-by-step explanation:

To calculate the resistance of a 0.01N solution of an electrolyte with equivalent conductivity of 420Ω⁻¹cm²equiv⁻¹ and a cell constant of 0.88cm⁻¹, we need to utilize the following formula:

Resistance (R) = 1 / (Equivalent Conductivity (\u03ba) × Cell Constant (G))

In this instance, we would substitute 420Ω⁻¹cm²equiv⁻¹ for \u03ba and 0.88cm⁻¹ for G:

R = 1 / (420 × 0.88)

This calculation results in:

R = 1 / 369.6

R = 0.0027Ω, or 2.7mΩ

Therefore, the resistance of the electrolyte solution is 2.7mΩ.