Question

Assume that int x = 50; int y = 20 and int z = 6, what is the result of x / y / z?

A) 0
B) 12
C) 16
D) a syntax error as this is syntactically invalid

Answer 1

The expression x / y / z with int x = 50, int y = 20, and int z = 6 in integer division results in 0 because 50 divided by 20 equals 2.5 (truncated to 2), and then 2 divided by 6 is truncated to 0.

Step-by-step explanation:

Given the variables int x = 50, int y = 20, and int z = 6, the question asks for the result of the expression x / y / z. In programming, the division operation follows a left-to-right associativity, meaning that the operations are evaluated from left to right.

First, x is divided by y (50 / 20), which results in 2.5. Since the variables are of type int, this intermediate result is truncated to 2 (only the integer part is kept).

Next, this intermediate integer result (2) is divided by z (2 / 6). Since 2 is less than 6 and we are working with integer division, the result of 2 / 6 also truncates to 0.

Hence, the final result of x / y / z is 0, which corresponds to option A.