Question

What is the output of the following code fragment?

int i = 1;
int j = 1;
while (1 < 5) {
i++;
j = j *2;
}
.printin(j);
A) 64
B) 42
C) 16
D) 4
E) 8

Answer 1

The output of the given code fragment is 32.

Step-by-step explanation:

The output of the given code fragment can be calculated by following the loop and keeping track of the values of variables i and j. Initially, i is set to 1 and j is set to 1. The loop condition is 1 < 5, which is always true. In each iteration of the loop, i is incremented by 1 and j is multiplied by 2. This process continues until the loop condition becomes false, which occurs when i becomes 5. Therefore, the final value of j is calculated as 1 * 2 * 2 * 2 * 2 * 2, which results in 32.