The difference in the initial values of the functions in the example is 17°F.
How do we find the difference in the initial values of the functions in the example?
From the information provided, the temperature at 5:00 AM is 63°F. The table shows that the temperature at 5:00 PM is 80°F.
Difference = Evening Temperature − Morning Temperature
Difference = 80°F − 63°F
Difference = 17°F
The difference in the initial values of the temperature function from 5:00 AM to 5:00 PM is 17°F.
The Full question
At 5 am the temp is 63 f. Temp increases at an average rate of 1.5 f each hour for the next 5 hours of the morning. After 5 pm the temp starts to decrease the table show the average rate that the temp decreases.
5:00 PM 6:00 PM 7:00 PM 8:00 PM 9:00PM
80°F 78°F 76°F 74°F 72°F
rate of change in the morning: 1.5
rate of change rate in the evening = (y₁ - y₂)/(x₁-x₂) = (78 - 80)/(6 - 5) = -2/1 = -2.
|-2| > |1.5|
The temperature changes at a greater average rate in the evening
What is the difference in the initial values of the functions in the exampl?