Final answer:
The least of four consecutive even integers whose sum is 236 is 58. We find this through an equation representing the sum of these integers and solving for the least integer.
Step-by-step explanation:
To find the least of four consecutive even integers that add up to 236, we can create an equation to represent this situation. Let's designate the least integer as x. Then the four integers can be represented as x, x+2, x+4, and x+6. The sum of these integers is given by the equation:
x + (x + 2) + (x + 4) + (x + 6) = 236.
Solving for x, we combine like terms:
4x + 12 = 236
4x = 224
x = 56
Therefore, the least integer is 58, since 56 is not an even number and we are looking for the even sequence starting from 58 which is option B) 58.