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A quadratic function with a constant second difference of 2 and a y-intercept of -16 can be represented in the form y = ax^2 + bx + c, where a, b, and c are constants. The specific quadratic equation is determined by these coefficients.

User Res
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Final answer:

The question involves finding a quadratic function with a second difference of 2 and a y-intercept of -16, which suggests the equation y = x^2 + bx - 16. The coefficient a is 1 due to the second difference, and c is -16 from the y-intercept, while b is unknown.

Step-by-step explanation:

The student's question pertains to a quadratic function with a given constant second difference and a specified y-intercept. This indicates that the function is of the form y = ax^2 + bx + c, where a, b, and c represent the coefficients of the equation.

The constant second difference of 2 suggests that the coefficient a in the quadratic equation is 1. That's because the second difference in a quadratic function equals 2a, and since it is given as 2, we can deduce that a must be equal to 1. With a y-intercept of -16, we can identify c as -16. The coefficient b is not specified and could be any real number. Therefore, the specific quadratic equation would be y = x^2 + bx - 16, where b is an undetermined real number.

The Solution of Quadratic Equations

Quadratic equations are often solved using the quadratic formula, which is x = (-b ± √(b^2 - 4ac)) / (2a). The formula provides the solutions to any quadratic equation of the form ax^2 + bx + c = 0. In our specific case of y = x^2 + bx - 16, if we needed to find the values of x where y equals zero, we would substitute our known values into the quadratic formula to find the solutions.

User HardikS
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