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A 215-N box is placed on an inclined plane with a 35° angle. Find the component of the weight force parallel to the plane's surface.

(a) 184 N
(b) 123 N
(c) 167 N
(d) 95 N

1 Answer

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Final answer:

The component of the weight force parallel to the inclined plane's surface can be calculated using the formula w = mg × sin(θ), where m is the mass of the object and θ is the angle of the inclined plane.

Step-by-step explanation:

When an object sits on an inclined plane, the weight force can be resolved into perpendicular and parallel components. The component of the weight force parallel to the plane's surface can be calculated using the formula:

w = mg × sin(θ)

where w is the component of the weight force parallel to the plane's surface, m is the mass of the box, g is the acceleration due to gravity (approximately 9.8 m/s²), and θ is the angle of the inclined plane.

In this case, the mass of the box is not given, so we cannot calculate the exact value of the component of the weight force parallel to the plane's surface. Therefore, none of the given options (a) 184 N, (b) 123 N, (c) 167 N, (d) 95 N, can be considered as the correct answer.

User Paul Dixon
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