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h(s) = 1 + √(s \ ) / 1 - √(s)
differentiate using quotient rule ​

User Dimbo
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1 Answer

10 votes

Answer:


h^(l) (s) = (1 )/((√(s)) (1-√(s))^(2) )

Explanation:

Explanation

Given that


h(s) = (1+√(s) )/(1-√(s) )

Differentiating equation (i) with respective to 'x' ,we get


h^(l) (s) =(1-√(s)) (1)/(2√(s) ) -(1+√(s))((-1)/(2√(s) )) )/((1-√(s))^(2) )


h^(l) (s) = ((1)/(2√(s) ) -(1)/(2√(s) )X√(s) + (1)/(2√(s) ) +(1)/(2√(s) )X√(s) )/((1-√(s))^(2) )


h^(l) (s) = ((2)/(2√(s) ) )/((1-√(s))^(2) )


h^(l) (s) = (1 )/((√(s)) (1-√(s))^(2) )

User Hirowatari
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