Question

Which linear function equation below would contain the points (3, -2) and (6, 0)?

a) y = 2x - 8
b) y = -2x + 6
c) y = 2x + 4
d) y = 3x + 5

Answer 1

The linear function equation that contains the points (3, -2) and (6, 0) is y = (2/3)x - 4.

Step-by-step explanation:

The equation of a linear function is y = mx + b, where m is the slope and b is the y-intercept. To find the equation that contains the points (3, -2) and (6, 0), we need to calculate the slope and y-intercept.

Slope (m) = (y2 - y1) / (x2 - x1) = (0 - (-2)) / (6 - 3) = 2/3

Using the slope-intercept form y = mx + b, we can substitute one of the points into the equation and solve for the y-intercept:

-2 = (2/3)(3) + b

-2 = 2 + b

b = -4

So, the equation that contains the points (3, -2) and (6, 0) is y = (2/3)x - 4.