Final answer:
To create 9.3 moles of ammonia, 34.8 grams of nitrogen (N2) would be required.
Step-by-step explanation:
To determine the number of grams of nitrogen (N2) required to produce 9.3 moles of ammonia (NH3), we need to use the mole ratio from the balanced equation:
N2(g) + 3H2(g) -> 2NH3(g)
From the equation, we can see that for every 1 mole of N2, 2 moles of NH3 are produced. Therefore, the mole ratio is 1:2.
Using the mole ratio, we can set up a proportion:
(9.3 mol NH3 / 2 mol NH3) = (x g N2 / 1 mol N2)
Solving for x, we find that x = 34.8 grams. Therefore, the correct answer is A) 34.8 grams.