Final answer:
The temperature change of water when 3360 joules are absorbed by 100 g of water is 8°C, calculated using the specific heat capacity of water, which is 4.184 J/(g°C). The options provided in the question do not include the correct answer, indicating there may be a mistake in the question.
Step-by-step explanation:
To calculate the temperature change in degrees Celsius when 3360 joules are absorbed by 100 g of water, we use the specific heat capacity of water. The specific heat of water is approximately 4.184 J/(g°C). According to the formula q = mcΔT, where q is the heat in joules, m is the mass in grams, c is the specific heat capacity, and ΔT is the change in temperature, we can rearrange the formula to solve for ΔT:
ΔT = q / (mc)
ΔT = 3360 J / (100 g × 4.184 J/(g°C))
ΔT = 3360 J / 418.4 J/°C
ΔT = 8°C
Therefore, the temperature change of water when 3360 joules are absorbed is 8°C. Thus, none of the options A) 12°C, B) 20°C, C) 40°C, D) 80°C is correct. The question might have a mistake or a typo.