32.9k views
4 votes
Is iodine-131 a radioactive material that decays according to the function a(t), where a₀ is the initial amount present and a is the amount present at time t (in days)?

a. Yes, it undergoes radioactive decay.

b. No, it remains stable over time.

c. It decays according to the inverse square law.

d. The decay is linear with time.

User Ben Cheng
by
8.2k points

1 Answer

3 votes

Final answer:

Iodine-131 is a radioactive material that decays in an exponential manner with a half-life of 8.02 days. The decay follows a first-order kinetic model, not linear, and the decay constant is 0.138 d⁻¹, which helps estimate the decay over time.

Step-by-step explanation:

Iodine-131 is indeed a radioactive material that decays over time. The correct answer to whether Iodine-131 decays according to the function a(t) is a. Yes, it undergoes radioactive decay. Iodine-131 exhibits first-order radioactive decay, characterized by an exponential decrease in the amount remaining over time, not a linear or inverse square law decay. The half-life of Iodine-131 is 8.02 days, which means that every 8.02 days, the amount of Iodine-131 will reduce to half its previous amount.

The decay constant for Iodine-131 is 0.138 d⁻¹, which can be used to estimate the time it will take for a certain percentage of Iodine-131 to decay. For instance, to calculate how many days it will take for 90% of Iodine-131 to decay, you can use the decay constant in a first-order decay equation.

User Jorge Paredes
by
7.9k points