Question

Let X be normally distributed with mean μ=2,700 and standard deviation σ=900. [You may find it useful to reference the

Find x such that P(2,700≤X≤x)=0.1217. (Round your final answer to nearest whole number.)

Answer 1

To find x such that P(2,700≤X≤x)=0.1217, we use the standard normal distribution table and the z-score formula. The value of x is approximately 2079.

Step-by-step explanation:

To find x such that P(2,700≤X≤x)=0.1217, we can use the standard normal distribution table and the z-score formula. First, we calculate the z-score corresponding to the given probability: z = invNorm(0.1217) = -1.1622 (rounded to four decimal places). Then, we use the formula z = (x - μ) / σ to solve for x. Plugging in the given values, we have -1.1622 = (x - 2700) / 900. Solving for x, we find that x ≈ 2078.78 (rounded to the nearest whole number).