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Suppose 13% of students are veterans and 133 students are involved in sports. How unusual would it be to have no more than 12 veterans involved in sports? (12 veterans is about 9.0226%)

a. P(X ≤ 12) = 0.090226
b. P(X > 12) = 0.909774
c. P(X ≤ 12) = 0.909774
d. P(X > 12) = 0.090226

1 Answer

2 votes

Final answer:

The question asks for the probability of having no more than 12 veterans in sports, given 13% of students are veterans. P(X ≤ 12) = 0.909774 indicates a high chance of having at most 12 veterans, making it 'not unusual'. The correct answer should reflect this high probability.Option C is the correct answer.

Step-by-step explanation:

To determine how unusual it would be to have no more than 12 veterans involved in sports, we need to compute the probability of having at most 12 veterans among those involved in sports, given that the percentage of student veterans is 13%.

This is a problem of probability, where the number of veterans involved in sports is a random variable. To solve this, we can use the binomial probability formula if we assume the selection of students for sports is independent from being a veteran, which is likely a simplification but common in such probability exercises.

The question suggests that we need to find P(X ≤ 12), where X is the number of veterans in sports. However, we see some other terms and symbols that are misleading in this context, such as P(X > 12) and specific probabilities listed as options a, b, c, and d. Option c, P(X ≤ 12) = 0.909774, implies that there is about a 91% chance that there will be at most 12 veterans involved in sports. This scenario is 'not unusual' due to the high probability.

User Ben Holland
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