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Christopher has 7 chores to do. If each chore does not depend on the others, in how many different orders could he do the chores?

A) 7
B) 14
C) 21
D) 49

User Buc
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1 Answer

2 votes

Final answer:

The number of different orders in which Christopher can do 7 independent chores is calculated by the permutation of 7, which is 7 factorial (7!). This results in 5040 different orders, which is not listed in the multiple-choice options provided. None of the given option is correct.

Step-by-step explanation:

The question is asking for the number of different orders in which Christopher can do his 7 chores, where each chore is independent of the others. This is a classic example of a permutation since the order in which the chores are done matters.

To calculate the permutations of 7 chores, we use the factorial function of 7, represented as 7!. The factorial of a number, n!, is the product of all positive integers less than or equal to n. So, 7! = 7 × 6 × 5 × 4 × 3 × 2 × 1.

7! = 5040

Therefore, Christopher can complete his chores in 5040 different orders. Looking at the multiple-choice answers provided, none of them match this result. Hence, an option with the correct answer is not listed. The correct answer would be 'None of the above'.

User Mbrevoort
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