Final answer:
The product of the reaction between OH- and CH3CH2CH2Br is CH3CH2CH2OH, as the hydroxide ion replaces the bromide ion in an S_N2 reaction.
Step-by-step explanation:
The organic product of the nucleophilic substitution reaction between OH− and CH3CH2CH2Br is CH3CH2CH2OH. In this reaction, the hydroxide ion (OH−) acts as the nucleophile which displaces the bromide ion (Br−) from the bromoalkane CH3CH2CH2Br. The hydroxide ion attaches to the carbon previously bonded to the bromine, resulting in the alcohol product CH3CH2CH2OH. As the reaction follows an SN2 mechanism, it involves a single step where the bond-making and bond-breaking processes happen concertedly, typically with inversion of stereochemistry at the reactive carbon center.
The correct answer to the question is hence: A) CH3CH2CH2OH