Answer: 3
Explanation:
You are solving a system of equations y1 = abx1 and y2 = abx2, so plug the x and y coordinates into the equations to solve for a and b:6 = ab1 & 3/4 = ab-2Since a = 6/b, we can use this in the second equation to solve for b:3/4 = (6/b)b-23/4 = 6/b36/(3/4) = b38 = b32 = b,which means that a = 3.Now we just input our a and b values into y = abx, so our equation is y = 3*2x. I hope this helps