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Calculate the tension in the wire supporting the 9.51 kg disco ball when the elevator is accelerating upwards with an acceleration of = 1 . 3 0 m / s 2 a= 1.30 m/s 2

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Final answer:

The tension in the wire supporting the 9.51 kg disco ball when the elevator is accelerating upwards with an acceleration of 1.30 m/s² is 93.348 N.

Step-by-step explanation:

To calculate the tension in the wire supporting the 9.51 kg disco ball when the elevator is accelerating upwards with an acceleration of 1.30 m/s², we can use Newton's second law of motion.

The equation to calculate tension is T = mg + ma, where T is the tension, m is the mass, g is the acceleration due to gravity, and a is the acceleration of the elevator.

In this case, the mass of the disco ball is 9.51 kg and the acceleration of the elevator is 1.30 m/s². The acceleration due to gravity is approximately 9.8 m/s². Plugging these values into the equation, we get T = (9.51 kg)(9.8 m/s²) + (9.51 kg)(1.30 m/s²) = 93.348 N.

Therefore, the tension in the wire supporting the disco ball is 93.348 N.

The tension in the wire supporting a 9.51 kg disco ball when the elevator is accelerating upwards with an acceleration of 1.30 m/s2 can be calculated using Newton's second law of motion.

The total force on the ball due to gravity and the acceleration of the elevator is the weight of the ball plus the force due to the elevator's acceleration. The formula for tension (T) is T = m(g + a), where m is the mass of the disco ball, g is the acceleration due to gravity (approximately 9.81 m/s2), and a is the acceleration of the elevator.

The calculation will be T = 9.51 kg * (9.81 m/s2 + 1.30 m/s2) which equals T = 9.51 kg * 11.11 m/s2. This results in a tension of approximately 105.6 N.

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