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A firecracker, initially at rest, explodes into two fragments. The first, of mass 17g, moves in the positive x direction at 39m/s. The second moves at 26m/s.

A) What is the total momentum of the system?
B) What is the velocity of the second fragment?
C) What is the kinetic energy of the system?
D) What is the mass of the second fragment?

User Havchr
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1 Answer

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Final answer:

A) The total momentum of the system is 0.663kg•m/s. B) The velocity of the second fragment can only be determined if its mass is known. C) The kinetic energy of the system is 12.441 Joules. D) The mass of the second fragment cannot be determined without additional information.

Step-by-step explanation:

A) To find the total momentum of the system, we can calculate the sum of the individual momenta of the fragments. The momentum of an object is given by the product of its mass and velocity. The first fragment has a mass of 17g (0.017kg) and a velocity of 39m/s. Therefore, its momentum is 0.017kg * 39m/s = 0.663kg•m/s. The second fragment's mass is not given, so we cannot calculate its momentum.

B) The velocity of the second fragment can be calculated by using the principle of conservation of momentum. In an explosion, the total momentum before the explosion is zero. Therefore, the momentum of the first fragment must be balanced by the momentum of the second fragment. Since the total momentum is zero, the momentum of the second fragment is -0.663kg•m/s. Using the mass of the second fragment, we can calculate its velocity using the formula mv = -0.663kg•m/s. However, we don't have enough information to find the mass of the second fragment.

C) The kinetic energy of the system can be calculated by summing the individual kinetic energies of the fragments. The kinetic energy of an object is given by the formula 1/2 * mass * velocity^2. For the first fragment, the kinetic energy is 1/2 * 0.017kg * (39m/s)^2 = 12.441 Joules. The kinetic energy of the second fragment cannot be calculated without knowing its mass.

D) The mass of the second fragment is not provided in the given information. Therefore, we cannot determine its mass.

User Babette
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