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Assuming x=2 and y=0, what is the square root of 16x³y⁶?
a) 0
b) 8
c) 16
d) 32

1 Answer

4 votes

Final answer:

Given x=2 and y=0, the square root of 16x³y⁶ simplifies to 16*8*0, which is 0, and the square root of 0 is 0, so the answer is a) 0.

Step-by-step explanation:

Assuming x=2 and y=0, the square root of 16x³y⁶ is calculated as follows:

Substitute the given values for x and y into the expression, resulting in 16*(2)³*(0)⁶.

Calculate the exponent for x, which gives us (2)³ = 8.

Note that any number raised to the power of zero is 1, and the product of any number and zero is zero, so (0)⁶ is zero, and multiplying by zero results in zero.

The expression simplifies to 16*8*0, which equals 0.

The square root of 0 is still 0, so the final answer is 0.

Therefore, the correct answer is a) 0.

To find the square root of 16x³y⁶, we need to substitute the given values of x and y into the expression and simplify. With x = 2 and y = 0:

16x³y⁶ = 16(2)³(0)⁶ = 16(8)(0) = 0

So the square root of 16x³y⁶ is 0. Therefore, the correct answer is (a) 0.

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