Final answer:
To determine the volume of a 0.750 M Cu(NO3)2 solution from 8.62 g of solute, the molar mass of Cu(NO3)2 is used to calculate the number of moles and then the volume, which is found to be 61.28 mL, a choice not listed in the given options.
Step-by-step explanation:
To find the volume of the solution we need to calculate from the given mass of CuNO3 and the desired molarity of the solution (0.750 M). The molar mass of CuNO3 needs to be calculated, but this seems to be a typographical error since the correct chemical formula for copper(II) nitrate is Cu(NO3)2. Assuming CuNO3 is indeed intended to be Cu(NO3)2, and using its molar mass (187.55 g/mol), we can find the number of moles of Cu(NO3)2 in 8.62 g.
The number of moles (n) is:
n = mass / molar mass = 8.62 g / 187.55 g/mol = 0.04596 mol
Using the formula Molarity (M) = moles of solute (mol) / volume of solution (L), we can solve for the volume.
0.750 M = 0.04596 mol / volume (L)
Volume = 0.04596 mol / 0.750 M = 0.06128 L
Converting liters to milliliters, we get:
Volume = 0.06128 L x 1000 mL/L = 61.28 mL
This option is not listed among the given choices, indicating there might have been an error in either the question or the choices provided.