Question

To accelerate an electron from a velocity of 2.00×106 m/s to 9.00×106 m/s, what potential difference must the electron pass through?

Answer 1

To calculate the potential difference, we can use the equation: V = (1/2)mv^2 / q. Using the given values, the potential difference is -19 V.

Step-by-step explanation:

To calculate the potential difference, we can use the equation:

V = (1/2)mv^2 / q

Where V is the potential difference, m is the mass of the electron, v is the change in velocity, and q is the charge of the electron.

Using the given values:

m = 9.11 × 10^-31 kg

v = 9.00 × 10^6 m/s - 2.00 × 10^6 m/s = 7.00 × 10^6 m/s

q = -1.60 × 10^-19 C

Plugging in these values, we get:

V = (1/2)(9.11 × 10^-31 kg)(7.00 × 10^6 m/s)^2 / (-1.60 × 10^-19 C)

Simplifying the equation, we find:

V = -19 V