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The charge center of a thundercloud, drifting 3.0 km above the earth's surface, contains 20 C of negative charge. Assuming the charge center has a radius of 1.0 km, and modeling the charge center and the earth's surface as parallel plates, calculate the capacitance of the system. Calculate the potential difference between charge center and ground.

User Jschoi
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Final answer:

To calculate the capacitance and potential difference of the thundercloud-earth system modeled as a parallel-plate capacitor, the area of the charge center and the distance to Earth's surface is used along with the permittivity of free space.

Step-by-step explanation:

The charge center of a thundercloud, which contains 20 C of negative charge and is located 3.0 km above Earth's surface, can be considered as one plate of a capacitor with Earth's surface as the other plate.

Given that the charge center has a radius of 1.0 km, we can use the formula for the capacitance of a parallel-plate capacitor to calculate the capacitance of the system:


C = ε0A/d

Where:

  • C is the capacitance,
  • ε0 is the permittivity of free space (ε0 = 8.85 x 10-12 F/m),
  • A is the area of the plates, and
  • d is the separation between the plates.

For a radius r of 1.0 km, the area A is πr2 = π3.14 x 106 m2. The separation d is 3.0 km = 3000 m.

The potential difference V can then be found from the relationship Q = CV, where Q is the charge on the plates (20 C).

The capacitance C is therefore calculated as:

C = (8.85 x 10-12 F/m)(π3.14 x 106 m2)/3000 m = 9.25 x 10-9 F

The potential difference V is given by:

V = Q/C = 20 C / 9.25 x 10-9 F = 2.162 x 109 V

User EtherDragon
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