Final answer:
The general linear equation is Ax + By + C = 0, where A = 1, B = -5, and C = 8. The general linear equation of the line with a slope of 1/5 that passes through the point (2,2) is x - 5y + 8 = 0. This is found by using the point-slope form and rearranging it into standard form.
Step-by-step explanation:
To find the equation of a straight line passing through a given point and having a given slope, we can use the point-slope form of a linear equation. The point-slope form is given by y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.
Given that the point is (2,2) and the slope is 1/5, we have: y - 2 = (1/5)(x - 2)
Expanding and rearranging this equation, we get:
5(y - 2) = x - 2
5y - 10 = x - 2
x - 5y + 8 = 0
Therefore, the general linear equation of the straight line passing through the point (2,2) and having a slope of 1/5 is Ax + By + C = 0, where A = 1, B = -5, and C = 8.