Final answer:
The probability of having 5 female babies in a row, given equal likelihood and independent events, is found by multiplying 0.5 five times (0.5^5) which equals 0.03125, making option b the correct answer.
Step-by-step explanation:
The probability of having 5 female babies in a row, given equal likelihood of a healthy pregnancy at each conception, can be calculated using the rule of multiplication for independent events if we assume the sex of each baby is independent of the others. The probability of having a girl is generally taken as 0.5 (or 50%). To find the probability of having five girls in a row, we would multiply the individual probabilities: 0.5 (first girl) × 0.5 (second girl) × 0.5 (third girl) × 0.5 (fourth girl) × 0.5 (fifth girl), which equals 0.5^5. Performing this calculation, we get 0.5^5 = 0.03125.
Therefore, option b, 0.03125, is the correct probability of having 5 female babies in a row under these conditions.
Probability is a measure of the likelihood of an event to occur. Many events cannot be predicted with total certainty. We can predict only the chance of an event to occur i.e., how likely they are going to happen, using it.
Probability can range from 0 to 1, where 0 means the event to be an impossible one and 1 indicates a certain event. Probability for Class 10 is an important topic for the students which explains all the basic concepts of this topic. The probability of all the events in a sample space adds up to 1.